5x^2+5x=3x^2+1

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Solution for 5x^2+5x=3x^2+1 equation:



5x^2+5x=3x^2+1
We move all terms to the left:
5x^2+5x-(3x^2+1)=0
We get rid of parentheses
5x^2-3x^2+5x-1=0
We add all the numbers together, and all the variables
2x^2+5x-1=0
a = 2; b = 5; c = -1;
Δ = b2-4ac
Δ = 52-4·2·(-1)
Δ = 33
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{33}}{2*2}=\frac{-5-\sqrt{33}}{4} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{33}}{2*2}=\frac{-5+\sqrt{33}}{4} $

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